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7n^2+2n-24=0
a = 7; b = 2; c = -24;
Δ = b2-4ac
Δ = 22-4·7·(-24)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-26}{2*7}=\frac{-28}{14} =-2 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+26}{2*7}=\frac{24}{14} =1+5/7 $
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